posted on 2013-07-22, 00:00authored byThorsten Gehrmann, Julio Lloret-Fillol, Heike Herrmann, Hubert Wadepohl, Lutz H. Gade
The N–N bond in the zirconium
hydrazinediido(2−)
complex [Zr(N2TBSNpy)(NNPh2)(py)] (1) is readily cleaved by one-electron oxidation.
Reacting [Zr(N2TBSNpy)(NNPh2)(py)] (1) with 0.5 molar equiv of iodine led to the
release of molecular N2 and yielded the mixed diphenylamido/iodo
complex [Zr(N2TBSNpyNPh2)(I)] (2). Exposure of hydrazinediide 1 to an excess of iodine resulted in further oxidation of the diphenylamido
ligand, yielding the diiodo complex 3 and tetraphenylhydrazine.
Similar reactivity was observed in the reaction of 1 with
diphenyl diselenide and diaryl disulfides, which reacted to give the
corresponding diphenylamido/arylchalcogenido complexes [Zr(N2TBSNpyNPh2)(SePh)] (4a) and [Zr(N2TBSNpy)(NPh2)(SAr)] (Ar = Ph (4b), C6F5 (4c)) along with N2. The reactions were also carried
out on an NMR scale with a 15Nα-labeled
hydrazido complex (1-15N). In all cases a single 15N NMR resonance at
310.16 ppm, assigned to 15N2, indicated the
formation of dinitrogen from the Nα atom in the hydrazide.
A crossover labeling experiment employing a 1:1 mixture of 1 and 15Nα-labeled 1-15N revealed that the isotope distribution
is, as expected, statistical 1:2:1 (14N2: 14/15N2: 15N2), which is consistent
with a reaction pathway involving a dinuclear intermediate in the
dinitrogen-forming step. Complex 1 reacted with N2O to give a mixture of two compounds, the bis(diphenylamido)
complex 6 and the doubly bridged μ-oxo complex 7. In contrast, reaction of 1 with 1 molar equiv
of pyridinium N-oxide only gave the doubly bridged
μ-oxo complex 7 along with 2,2′-bipyridine
and diphenylamine.