posted on 2017-08-16, 18:09authored byJiaxiang Chu, Chen Wang, Li Xiang, Xuebing Leng, Yaofeng Chen
Scandium
terminal imido complex [(NNNN)ScNDIPP] (2; NNNN
= [MeC(N(DIPP))CHC(Me)(NCH2CH2NMeCH2CH2NMe2)]−, DIPP = 2,6-iPr2C6H3)
reacts with 9-borabicyclononane (9-BBN) to give scandium
borohydride [(NNNN(B)H)Sc(N(H)DIPP)] (3; NNNN(B)H = [MeC(N(DIPP))CHC(Me)(NCH2CH2NMeCH2CH2N(Me)CH2(BBN)]2–), and C(sp3)–H bond
borylation of the NNNN ligand occurs during this reaction. In contrast,
the reaction between complex 2 and catecholborane (CatBH)
gives scandium catecholate [(NNNN)Sc(Cat)] (4), and B–O
bond cleavage happens during this reaction. Both 3 and 4 have been well-characterized including the single-crystal
X-ray diffraction analysis. Reaction of 2 with bis(catecholato)diboron
(CatB–BCat) also gives a B–O bond cleavage product.