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Heteronuclear Hexaplatinum Cluster Complexes:  Structure as a Function of Electron Count

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posted on 1998-09-24, 00:00 authored by Greg J. Spivak, Jagadese J. Vittal, Richard J. Puddephatt
The 84-electron hexaplatinum cluster complex [Pt<sub>6</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>], <b>1</b>, dppm = Ph<sub>2</sub>PCH<sub>2</sub>PPh<sub>2</sub>, reacts in a 1:2 molar ratio with either 0-electron metalloligands LM<sup>+</sup> (L = Ph<sub>3</sub>P, M = Cu, Ag, Au; L = <i>i</i>Pr<sub>3</sub>P, M = Au) or InX<sub>3</sub> (X = Cl, Br) or 2-electron metalloligands Tl<sup>+</sup> and Hg to give the corresponding 84-electron clusters [Pt<sub>6</sub>(μ<sub>3</sub>-ML)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]<sup>2+</sup> or [Pt<sub>6</sub>(μ<sub>3</sub>-InX<sub>3</sub>)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>] or 88-electron clusters [Pt<sub>6</sub>(μ<sub>3</sub>-Tl)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]<sup>2+</sup> and [Pt<sub>6</sub>(μ<sub>3</sub>-Hg)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>], respectively. The mercury cluster is oxidized by CH<sub>2</sub>I<sub>2</sub> to give the known 86-electron cluster [Pt<sub>6</sub>(μ<sub>3</sub>-HgI)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]. Reaction of <b>1</b> with [Ir(CO)<sub>4</sub>]<sup>-</sup> occurs in a 1:1 ratio only to give the 98-electron anionic cluster [Pt<sub>6</sub>{μ<sub>3</sub>-Ir(CO)<sub>2</sub>}(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]<sup>-</sup>, which reacts with [Ph<sub>3</sub>PAu]<sup>+</sup> to give [Pt<sub>6</sub>{μ<sub>3</sub>-Ir(CO)<sub>2</sub>}(μ<sub>3</sub>-AuPPh<sub>3</sub>)(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]. The new cluster complexes are characterized by NMR and IR spectroscopies, and [Pt<sub>6</sub>(μ<sub>3</sub>-AuP<i>i</i>Pr<sub>3</sub>)<sub>2</sub>(μ-CO)<sub>6</sub>(μ-dppm)<sub>3</sub>]<sup>2+</sup> is also characterizedby an X-ray structure determination.

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